17. Mirror / Invert a Binary Tree ⭐
Swaps the left and right child pointers of every node in the binary tree recursively (famous Google interview problem).
Live loop — open the studio to scrub, add your own array, or race it in Battle Arena.
Asked in interviews at
Reference implementation (Python)
def invert_tree(root):
if not root:
return None
root.left, root.right = root.right, root.left
invert_tree(root.left)
invert_tree(root.right)
return rootEmbed this visualization
Drop a live, looping 17. Mirror / Invert a Binary Tree ⭐ canvas into a blog post or course page.
<iframe src="/embed/invert-tree" width="100%" height="380" style="border:1px solid #e6e8ec;border-radius:14px" loading="lazy" title="3D algorithm visualization by CodeWithMunnaX"></iframe>Frequently asked
What is the time and space complexity of 17. Mirror / Invert a Binary Tree ⭐?
17. Mirror / Invert a Binary Tree ⭐ runs in O(n) time and O(h) auxiliary space.
Is the 17. Mirror / Invert a Binary Tree ⭐ visualizer free?
The core 3D visualizer, Web Audio chimes and step intuition are free. A one-time ₹49 Pro Pass unlocks advanced algorithms, large custom arrays, Battle Arena and reel export.
Which companies ask 17. Mirror / Invert a Binary Tree ⭐ in interviews?
17. Mirror / Invert a Binary Tree ⭐ shows up in interviews at Google, Twitter, Amazon.
How does the 3D visualization of 17. Mirror / Invert a Binary Tree ⭐ work?
Each array value becomes a 3D pillar whose height maps to its value. Comparisons glow amber, swaps flash red, and settled elements lock green while a floating pointer badge tracks the active index — synchronized line-by-line with the Python code.