7. Count Leaf Nodes
Enumerates all terminal leaf nodes where both left and right child pointers are null.
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Asked in interviews at
Reference implementation (Python)
def count_leaves(root):
if not root:
return 0
if not root.left and not root.right:
return 1
return count_leaves(root.left) + count_leaves(root.right)Embed this visualization
Drop a live, looping 7. Count Leaf Nodes canvas into a blog post or course page.
<iframe src="/embed/tree-count-leaves" width="100%" height="380" style="border:1px solid #e6e8ec;border-radius:14px" loading="lazy" title="3D algorithm visualization by CodeWithMunnaX"></iframe>Frequently asked
What is the time and space complexity of 7. Count Leaf Nodes?
7. Count Leaf Nodes runs in O(n) time and O(h) auxiliary space.
Is the 7. Count Leaf Nodes visualizer free?
The core 3D visualizer, Web Audio chimes and step intuition are free. A one-time ₹49 Pro Pass unlocks advanced algorithms, large custom arrays, Battle Arena and reel export.
Which companies ask 7. Count Leaf Nodes in interviews?
7. Count Leaf Nodes shows up in interviews at Amazon, Apple, Stripe.
How does the 3D visualization of 7. Count Leaf Nodes work?
Each array value becomes a 3D pillar whose height maps to its value. Comparisons glow amber, swaps flash red, and settled elements lock green while a floating pointer badge tracks the active index — synchronized line-by-line with the Python code.